Probability Distributions
Conditional probability, Bayes theorem, random variables, binomial distribution — Maharashtra HSC Maths Ch 8 & 9
Board Exam Tips
- →Bayes theorem numerical (drawing balls from an urn, faulty machines) is a Maharashtra HSC 4-marker every year.
- →Binomial distribution — write PMF P(X = r) = ⁿCr pʳ qⁿ⁻ʳ and compute mean np and variance npq.
- →Random variable — construct probability distribution table, then compute E(X) = Σx·p(x), Var(X) = Σx²·p(x) − [E(X)]².
- →Conditional probability formula P(A|B) = P(A∩B)/P(B) is asked as a 2-marker every year.
- →State whether events are independent (P(A∩B) = P(A)P(B)) before applying formulas.
📐 Formulas(12)
Classical Definition
Addition Theorem★ Board fav
Conditional Probability★ Board fav
Multiplication Theorem
Total Probability Theorem★ Board fav
Bayes Theorem★ Board fav
Probability Distribution of Random Variable★ Board fav
Expectation (mean)★ Board fav
Variance and Standard Deviation
Binomial Distribution (PMF)★ Board fav
Binomial Mean and Variance
Independence
✏️ Solved Examples
A die is rolled. Find the probability that the outcome is (i) an even number, (ii) a prime number.
Sample space: S = {1, 2, 3, 4, 5, 6}, n(S) = 6.
In a factory, machine A produces 60% of the items, machine B produces 40%. Defect rates are 3% and 5% respectively. An item is picked at random and found defective. Find the probability that it was made by A. (Bayes' theorem)
Let A₁ = made by A, A₂ = made by B, D = defective.
A coin is tossed 10 times. Find the probability of getting exactly 6 heads. Also find mean and variance of the number of heads.
Binomial with n = 10, p = 1/2 (fair coin).
⚠️ Traps & Common Mistakes
- 1
Confusing P(A ∩ B) with P(A|B)
✓P(A|B) = P(A ∩ B)/P(B). They are different — the conditional restricts sample space.
- 2
Assuming events are independent without checking
✓Verify P(A ∩ B) = P(A)P(B). Never assume from context alone.
- 3
Using addition without subtracting intersection when events overlap
✓P(A ∪ B) = P(A) + P(B) − P(A ∩ B). Do not skip the third term unless mutually exclusive.
- 4
Applying binomial when n is not known or trials not independent
✓Binomial requires: fixed n, two outcomes, constant p, independent trials. Check all four.
- 5
Writing Var(X) = E(X²) + [E(X)]² instead of − [E(X)]²
✓Var(X) = E(X²) − [E(X)]². Minus sign is critical.
- 6
Forgetting Σp = 1 when constructing a probability distribution
✓Total column must sum to 1. If not, redo the table — probability of some outcome missed or an error.
🎯 Practice Yourself
- Q1
Two cards are drawn without replacement from a standard deck. Find P(both aces).
- Q2
A random variable X has P(X = 0) = 0.4, P(X = 1) = 0.3, P(X = 2) = 0.3. Find E(X).
- Q3
A binomial variable has n = 8, p = 1/3. Find variance.
- Q4
P(A) = 0.4, P(B) = 0.5, P(A ∩ B) = 0.2. Find P(A|B).
- Q5
A basket has 3 red and 5 white balls. Two balls are drawn without replacement. Find P(both same colour).
📝 Notes
Probability Distributions — Maharashtra HSC Overview
Chapter 8 (Probability distributions — random variables) and Chapter 9 (Binomial Distribution) of the Maharashtra Class 12 Mathematics textbook together cover conditional probability, Bayes theorem, discrete random variables, and binomial distribution.
Maharashtra syllabus specifics
- Bayes theorem numerical — Maharashtra HSC gives at least one 4-mark Bayes problem every year (urn/machine/disease context).
- Probability distribution table + E(X), Var(X) — Balbharati asks it as a 4-marker in every board paper.
- Binomial distribution derivation and mean/variance derivation (E(X) = np, Var(X) = npq) is a 3-marker.
- Random variable and its types — discrete vs continuous, with examples — is a Balbharati staple theoretical question.
Strategy
- Always list the sample space explicitly for simple problems.
- Distinguish P(A|B) from P(A ∩ B) — this is the #1 error in HSC.
- For Bayes problems, list all priors P(A_i) and likelihoods P(B|A_i) BEFORE substituting.
- For binomial distribution, verify n, p, q, independence conditions before applying the PMF.
- Show every step: writing the formula BEFORE substitution earns 1 mark.
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