Wave Optics
Huygens principle, interference, diffraction, polarisation — Maharashtra HSC Physics Ch 7
Board Exam Tips
- →Derivation of the fringe width formula for Young's double-slit experiment (β = λD/d) is asked in almost every HSC paper for 4 marks.
- →State and prove Malus's law (I = I₀cos²θ) for a 2-mark question — this is Maharashtra Board specific.
- →Diffraction at a single slit — condition for minima (a sinθ = nλ) and central maximum width — is a favourite 3-marker.
- →Distinguish clearly between interference (two coherent sources) and diffraction (single wavefront) — HSC frequently asks the comparison.
- →State Huygens' principle before deriving anything — it earns the introductory mark.
📐 Formulas(12)
Huygens' Principle★ Board fav
Path Difference for Interference
Conditions for Bright and Dark Fringes★ Board fav
Fringe Width★ Board fav
Intensity in Two-Source Interference
Ratio of Max to Min Intensity
Single-Slit Diffraction Minima★ Board fav
Width of Central Diffraction Maximum
Malus's Law★ Board fav
Brewster's Law★ Board fav
Resolving Power of a Microscope
Resolving Power of a Telescope
✏️ Solved Examples
In Young's double-slit experiment, slit separation is 0.5 mm, screen distance is 1 m, and wavelength of light is 600 nm. Find the fringe width.
Note quantities in SI units.
Two coherent sources produce intensities in the ratio 4 : 1. Find the ratio of maximum to minimum intensity in the interference pattern.
Amplitudes are proportional to √I.
Unpolarised light of intensity I₀ passes through three polarisers with successive axes at 30° to each other. Find the intensity emerging from the third polariser.
After the first polariser, half the intensity emerges.
⚠️ Traps & Common Mistakes
- 1
Using β = λ/d instead of λD/d
✓Fringe width is λD/d — do not drop the D.
- 2
Interchanging the conditions for diffraction minima (a sinθ = nλ) and interference maxima (d sinθ = nλ)
✓Interference maxima: d sinθ = nλ (n = 0, 1, 2, ...); diffraction MINIMA: a sinθ = nλ (n ≠ 0).
- 3
Applying Malus's law directly to unpolarised light
✓First polariser reduces intensity by half (I → I/2); Malus's law applies to the polarised beam from then on.
- 4
Forgetting the factor 2 in the width of the central diffraction maximum
✓W = 2λD/a. It is twice the width of a secondary maximum.
- 5
Confusing coherent sources with monochromatic sources
✓Coherent = constant phase difference. Monochromatic = single frequency. Coherence is stricter.
- 6
Using degrees in cos²θ when calculator is in radians (or vice versa)
✓Match calculator mode to units. Common numerical error.
🎯 Practice Yourself
- Q1
In YDSE, if wavelength is doubled and slit separation halved, by what factor does fringe width change?
- Q2
A single slit of width 0.1 mm is illuminated with light of λ = 500 nm. Find the angular width of the central maximum.
- Q3
Find Brewster's angle for glass of refractive index 1.5 (light travelling from air to glass).
- Q4
State Huygens' principle and use it to prove the law of reflection.
- Q5
In YDSE, sources of intensity ratio 9:1 interfere. Ratio of I_max to I_min?
📝 Notes
Wave Optics — Maharashtra HSC Overview
Chapter 7 of the Balbharati Class 12 Physics textbook covers the wave nature of light — Huygens' principle, interference, diffraction, polarisation, and resolving power.
Maharashtra-specific emphasis
- Malus's law derivation is asked frequently for 2 marks. The Balbharati book insists on the amplitude → intensity connection.
- Polarisation by scattering and plane of vibration vs plane of polarisation are treated more thoroughly than in NCERT.
- The resolving power of microscope and telescope are both in the syllabus with numericals — NCERT keeps it at conceptual level.
- Huygens' geometrical construction for reflection and refraction is expected to be drawn — the diagram alone carries 1 mark in a 4-mark derivation.
Common exam themes
- Two-slit intensity pattern combined with a single-slit envelope (i.e., the observed YDSE pattern is a product of interference and diffraction).
- Direct calculation of Brewster's angle from refractive index — simple 2-marker.
- Comparing interference vs diffraction in a tabular answer format.
Numerical tips
- Wavelengths are often given in nanometres (1 nm = 10⁻⁹ m). Convert before substituting.
- Angles in diffraction problems are usually small; use sinθ ≈ tanθ ≈ θ (in radians).
- Unpolarised light: assume half intensity passes the first ideal polariser, and Malus's law applies from the second onwards.
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