Integrals
Indefinite and definite integrals, standard forms, substitution, integration by parts, partial fractions — NCERT Class 12 Maths Ch 7
Board Exam Tips
- →Integration by parts (ILATE) is asked every year — typically as a 3- or 5-mark question.
- →Partial-fraction decomposition of a rational function shows up whenever the denominator factors nicely.
- →For definite integrals, use the property that ∫₀^a f(x) dx = ∫₀^a f(a − x) dx to simplify symmetric integrands.
- →Never forget the constant of integration +C in indefinite integrals — CBSE deducts a mark.
- →For trig integrals, memorise ∫ sec²x dx = tan x + C and ∫ cosec²x dx = −cot x + C — small standard forms rescue big problems.
📐 Formulas(14)
Power Rule★ Board fav
Integral of 1/x
Exponential and Logarithm
Standard Trig Integrals★ Board fav
Inverse Trig Integrals★ Board fav
Integration by Substitution★ Board fav
Integration by Parts★ Board fav
Partial Fractions (Linear factors)★ Board fav
Standard Form: 1/(x² + a²)★ Board fav
Standard Form: 1/(x² − a²)
Standard Form: 1/√(a² − x²)
Definite Integral (Fundamental Theorem)★ Board fav
Property: Reflection★ Board fav
Property: Even/Odd
✏️ Solved Examples
Evaluate ∫(3x² + 2x − 5) dx.
Apply the power rule term by term.
Evaluate ∫ x · e^x dx.
ILATE: Algebraic (x) before Exponential (e^x), so u = x, dv = e^x dx.
Evaluate ∫₀^{π/2} (sin x)/(sin x + cos x) dx.
Call the integral I and use the reflection property with a = π/2.
⚠️ Traps & Common Mistakes
- 1
Forgetting the constant of integration +C in indefinite integrals
✓Every indefinite integral MUST end in +C. It represents the family of antiderivatives.
- 2
Writing ∫ 1/x dx = ln x instead of ln|x|
✓The absolute value is essential — the antiderivative must be defined for negative x as well.
- 3
Applying the power rule with n = −1
✓The power rule requires n ≠ −1. For n = −1 use ∫ x^{-1} dx = ln|x| + C.
- 4
In integration by parts, choosing u as the harder function
✓Use ILATE: pick u from the leftmost class present (Inverse, Logarithm, Algebraic, Trig, Exponential). This usually makes ∫v du easier than the original.
- 5
In substitution, changing x but forgetting to change dx to du
✓u = g(x) ⇒ du = g'(x) dx. Substitute BOTH the function and its differential, or the limits (definite integral).
- 6
For definite integrals with substitution, forgetting to change limits
✓Either change limits to u-values, OR back-substitute to x before evaluating limits. Do not mix the two.
🎯 Practice Yourself
- Q1
Evaluate ∫ (x³ + 4x − 1)/x² dx.
- Q2
Evaluate ∫ x · sin x dx.
- Q3
Evaluate ∫ (2x + 3)/(x² + 3x + 5) dx.
- Q4
Evaluate ∫ dx/(x² + 6x + 13).
- Q5
Evaluate ∫₀^1 x·e^{x²} dx.
- Q6
Evaluate ∫ dx/((x − 1)(x − 2)) using partial fractions.
📝 Notes
Integrals
Integration reverses differentiation. Where the derivative measures instantaneous change, the integral accumulates it — giving area, distance, volume, work.
Two flavours of integral
- Indefinite integral ∫f(x) dx = F(x) + C: family of antiderivatives.
- Definite integral ∫_a^b f(x) dx = F(b) − F(a): a single number, the net signed area from a to b.
How to pick a technique
- Polynomial or standard form — direct formula from the table.
- You spot a function AND its derivative in the integrand — substitution.
- Product of an algebraic and a transcendental function — integration by parts (ILATE).
- Rational function P(x)/Q(x) with degree(P) < degree(Q) — partial fractions.
- Quadratic denominator — complete the square, then reduce to arctan or log form.
- Symmetric definite integral, limits 0 to a or −a to a — use the reflection or even/odd property.
The ILATE mnemonic
When choosing u in integration by parts, pick from the earliest available class:
- I — inverse trig (sin⁻¹, tan⁻¹, ...)
- L — logarithm (ln x, log x)
- A — algebraic (x, x², polynomial)
- T — trig (sin, cos, ...)
- E — exponential (e^x, a^x)
Whichever appears earlier in ILATE becomes u; the other becomes dv.
Sanity checks
- Differentiate your answer — you must get back the integrand.
- Missing +C on an indefinite integral costs a mark every time.
- If you replace x by (limit − x) in a definite integral and the integrand transforms nicely, the reflection property is likely the intended trick.
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